Answer key to UCEED 2018 Previous paper

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You may download UCEED 2018 question paper here

Detailed explanation to some of the design aptitude questions of UCEED 2018 are available in the below set of videos

Solutions for UCEED 2018 Exam paper 

1) 21

check the below image for explanation

How to solve?

It's difficult to memorize, esp because the ques will be on the screen. So, instead of looking for unique characters, try to find out repetitive characters. Start from the top row and after you complete the top row, move to the next row and so on. See if the symbol that you are checking had appeared in the previous rows. If so, then count it.

2) 113

The series represents the prime numbers between 100 and 170

3) 22

Near-vertical lines - 14

Near-horizontal lines - 4

lines inclined and slanting to right - 2

lines inclined and slanting to left - 3

4) 12

In the below image, the repeated patterns had been marked.

5) 6

In the below image, I had marked with colored lines the repetitions (same font), you can now count unique font types. 

Basically, whenever font questions like this one was asked, I observe the edges of the alphabets and see if any ther word follow the same trend as the alphabet considered. For ex. consider alphabets 'n' and 'g' in the green lined word 'mango', you can see the same trend followed in the word 'orange' marked again in green line. 

Observe the letter 'e' in apple is similar to 'e' in pineapple as well as 'pomogranate' but is different from 'e' in pear. 

I hope, you can find the similarity like this.

6) 49

cross section area of the larger cuboid of height 11 is 3X3

so, we better place some small cuboids such that it's area is 1X1, in other words, make length =2cm as height and height=1cm as length. with that the bottom portion will have a stack of 

3*3 = 9 small cuboids of height 2cm.

stacking another four rows above it will bring it to a height of 10cm. 

No. of small cuboids stacked as of now = 9*5 = 45

the larger cuboid now has only 1cm height. Now we have to fit the cuboids such that their height is always 1cm. The below image shows one possible arrangement. We can accommodate 4 cuboids.

So, total cuboids = 45 + 4 = 49

7) 7

Figure shows the two shapes separately and the union of the two such that their centroids lie on the same point. Since the torus outside diameter is smaller than the idli (cylinder), it's outer surface will be merged inside the cylinder when unioned. Also, the height of torus is 1cm greater than the cylinder and so the curved portion of the torus will project on top and bottom. Figure shows the top one. The same is symmetrical for bottom too. 

No. of surfaces on top = 1 (cylinder flat surface) + 1 (torus curved surface) +1 (circle at the center) = 3

No. of surfaces on bottom = 3 

No. of surfaces on sides = 1

Total = 3+3+1 = 7

8) 8

Height of a equilateral triange of size 3 = 

sqrt(square(3)-square(1.5)) ~ 2.6

Below image shows the arrangement.

9) 40

Image 1 (symmetry)

No. of triangles in image 1 = 12

Image 2

No. of triangles in red color = 4

No. of triangles in green color = 4

Image 3

No. of traingles = 4

Image 4

No. of triangles in green = 2

No. of triangles in purple = 2

Image 5

No. of triangles = 2

Image 6

No. of triangles = 4

Image 7

No. of triangles = 4

Image 8

No. of triangles = 2

Total = 12+8+4+4+2+4+4 = 40

10) 46

No. of stacked triangular pieces in 

Bottom rown = 9 (no. of triangles in top view)

2nd row (from bottom) = 9 

3rd row = 9-1 =8

4th row = 9-2 = 7

5th row = 9-3 = 6

6th row = 4

7th row = 2

8th row = 1

Total = 1+2+4+6+7+8+9+9 = 46

11) 11 

The smallest pulley is indicated by 'S' and it rotates in clockwise dorection as shown in the figure. 

Trick is as follows - Since the weight moves down, the direction of movement of the cable/rope is along the rope movement. In other words, the arrow head should be such that it is the front of the rope movement. It's best to count the circles following the direction of the rope from the weight. Else, you may get confused.

No. of pulleys wheeling in clockwise direction = 11 (indicated by numbers in order of count)

12) 65

Current time is 3 hr 10 mins

Time after 4 hrs and 40 mins will be (3+4) hrs and (10+40) mins

that will be 7 hrs 50 mins

In 1 hr (60 min), the hour hand would have moved to 30 degrees (360/12)

In 50 mins, the hour hand would move to 30*(50/60) = 25 degrees (from 7)

Angle of the hour hand = (7*30) + 25 = 235 

(beacuse the time is right now 7 hrs 50 mins and the hour hand is few degrees past/after 7)

Angle of the min hand = (10*30) = 300 degrees (since the min hand will be at 10 because it denotes 50 mins)

So, the angle between the hour and the minute hand  = 300 - 235 = 65 degrees

13) 8

flow - wolf

loin - lion

balm - lamb

bare - bear

god - dog

act - cat

tab - bat

tar - rat

14) 25

Easy accessing is indicated by the lesser no. of doors to be taken to reach the room. 

You can visually tell which room needs more doors to be passed. Yet, for a clear understanding I will list out the below

Rooms needing only one no. of door entry are 1,5,3,8,1310,12,14,17,19,20,21,22,27,28,26

Rooms needing two no.'s of door entry are 2,4,6,7,9,11,18,15,16,23

Rooms needing three no.'s of doors entry is 24

and Rooms needing four no. of doors entry is 25

15) 3

Figure shows the best path with less no. of doors on the way. Note that the doors that Riya crosses are W, R, S

16) 18

Considering the bottom surface (square formed by EFGH), no. of triangles = 4

No. of triangles on the sides (slant surface) = 4 (Surfaces IEH, IHG, IGF, IFE)

No. of triangles in the below image 

Red = 2 (I have shown only one, you can imagine the other)

Green = 2 (I have shown only one,you can imagine the other)

No. of triangles in the below image

Red = 2

Green = 1

No. of triangles in the below image

Red = 2

Green = 1

Total = 4+4+2+2+2+1+2+1 = 18

17) 19.23

I'm not sure whether there is any foolproof method for this kind of problems. But here i'm giving one possible solution by close observation.

Proportion of the the white rectangle = 6/4

Height of the red triangle = 2*breath of rectangle = 2*4 = 8 (coz the rectangle appears half height) 

Height of BC = twice the height of the red triangle = 2*8 = 16

Now, since the blabk triangles are in proportion to the square too, we can say 

BC/AC = 6/4

we know BC =16,

16/AC = 6/4

which gives, AC = 16*4/6 = 1037

16, 16*4/6 = 10.67

Length of AB = square_root(square(AC)+square(BC)) = sqrt(10.67^2 + 16^2) ~ 19.23

18) 36

T = toffe, L = lollypop, I = Ice cream

Mukund

2 T = 1 L

3I = 1 T

Ranjana

1 I =2 L

3 T = L

Sita has 1 L and wants the max T

Case I

If Sita exchanges with Ranjana first, she would get 3T

Case II

If Sita exchanges with Mukund first,

step 1: she exchanges and gets tofees with Mukund

she will gte 2T first, which she will exchange with mukund again to get 6I

Step 2:

She exchanges her 6I with Ranjana and gets 6*2 = 12L

Now, Sita exchanges 12L with Ranjana and gets 12*3 = 36T

19) 4

The figure shows the possibility

20) 10

Figure in the left shows the differences

21) B, C, D 

By observation 

22) B, D

Below figure shows the continuous line after removing spaces and special characters

Note that I had shown in 8 lines but they are all continuous. Here's the trick to find easily. Note that the options are Ghana, India, Peru, Iran 

that mean we need to look for the first letters G, I, P So, search from the beginning for these letters and stop when you encounter the letter, then look if you can find the name.

23) B, D

If Fredricks and Salunkhe investigate the same criminal (of the three), the remaining four will investigate the other two criminals such that Pradhyuman and Daya won't interrogate the same guy. So, based on this we can say that B and D ate fit

24) A,B, D

2+3 means 2 is the child of 3

2+3*1 means 1 is the wife of 3, so 2 has 3 as father and 1 as mother 

2+3*1+4 means 1 (the mother of 2) is the child (daughter) of 4. So, 2 is the grandchild to 4

2+3*1+4*5 means 5 is the wife of 4. Which means 5 is grandmother and 4 is grandfather to 2

So, options A, B and D are correct

25) A, C

The ques seems bit tricky but it isn't so. The thing is the given configuration of 30 circles are shown in top view and by the distance they mean how near to our eye in top view. In other words, they are not lying on the same plane (on the paper) but are arranged in 3D space according to the conditions given. 

It is clear that larger circles are farther from us. So, straight away ignore 11,2,3,9,10,19,4,20,1,12,18,21. 

Now, we need to check the remaining. 

Given, the thinner the circle the closer they are to us. 

So, circles 17, 22 should be near but since they are red, they must be far. 

So, circles 25 must be nearer (option A). OPtion B is definitely wrong. Also, 14 and 24 are of same thickness and both are red except that 24 is smaller in size and hence it must be near. Circle 6 is intensively thick that mean it is farther compared to 8, which is small as well as lesser thick.

26) A,B 

I guess I had included the details of this in this blog's illusion resource page

27) A, B

I don't think explanations are required for this

28) D

Keeping the two triangles shown in the below figure as reference, we first eliminate the unwanted option (A) Now, it is clear in option B and C that the position and pattern of the remaining triangles are not representing simple rotation.

29) A,B,C

Third statement says that all migrants in their country are not strong (men and women) and according to the second statement, some men are not strong. The fourth statement failed to say that women are included as migrants or not. It didn't gave any confirmation and hence there are no women migrants. So, all women are strong. 

B is also correct. C is obviously correct. D is certainly wrong for native men are also strong. 

30) A,B

31) A,B,C,D

32) A,B

Definitely, it doesn't show lust and the poet isn't happy with the current mode of marriage.

33) D

It is not clear whether C is correct or not for C means that a person just has doubt but doesn't signify its growth in future. So, D must be the correct answer.

34) B,C 

Theory precedes Practice means the theory is required for practice. But in the ques, it is never told like that. 'Practice is knowledge that comes by 'doing' which says that there is no element of theory in here. 

35) D

abhor means hatred.

36) A, B, D

37)

Not sure.

38) B,C 

You can learn more about tessellation problem solving here - 

39) A,C,D

Except L, all belong to Ajanta caves. (based on the color scheme followed)

40) C, D

Actually, they represent warli tribal art

41) B, D

Lol.. chlorine is given as an option :P

42) A, D

Learn more about solid manipulation here 

43) B,C

I don't have the patience to read this to answer, even if I was to give the exam, I would prefer to skip (and check at the end) than spending so much time on a single ques. Anyway, the answers are B,C as given in the official answer key.

44) A, B, C

By visual observation

45) B,C,D

I had given about convex and concave lenses applications in one of my resource page.

46) D

47) C

Obviously, Kerala is the smallest and Rajasthan is the biggest in terms of area.

48) A

star denotes the position where he took turn

49) A

50) C

Easy way

A you can see the poles of the sphere has black stripes crossing while the other color is not meeting there. So, in the given option, the pattern that has black ink on the top and bottom continuously shall be the required mapping

51) C

I recalled the usual punjabi wear (kurtha) of women and it turned out to be correct.

52) D

Checking the bat of the given pattern, - down ? down, up. So, the bat must be up in the top position in the ques mark. 

You need also have to check the position of the front leg and also his head. 

To learn how to deal with step by step animation making, refer this post 

53) D

54) D

55) D

Based on the landing angle (end slant line - approx. 30 degrees to the horizontal) of the letter (marked in red), we choose the option which exhibits the same pattern. Only D has that kind. 

56) B

Sometimes, ques like this might tend to confuse a lot coz the pattern has both the elements of rotation and numbers. Trying to find a pattern using numbers would eat your time and might make you feel the impossibility. It's always better to start with the rotation/orientation of the patterns

Below image shows the required pattern, You can also make the next pattern of required based on B and D.

57) B

Let us utilize the four patterns given in the options for explanations. 

1. Rotate figure clockwise by 90 degrees, then you will get the pattern shown in C
2. Flip new pattern (shown in option C) along its vertical axis, you get the pattern D
3. Flip the new pattern (option D) along the horizontal, you will get option B

58) D

Jim Corbett National Park is the oldest national park in India and was established in 1936 as Hailey National Park to protect the endangered Bengal tiger. It is located in Nainital district of Uttarakhand and was named after Jim Corbett who played a key role in its establishment.

Ranthambhore is the fortieth largest national park in northern India, located in Rajasthan. 

Kaziranga is a national park in the Golaghat and Nagaon districts of the state of Assam, India. The sanctuary, which hosts two-thirds of the world's great one-horned rhinoceroses, is a World Heritage Site.

Kanha National Park, is one of the tiger reserves of India and the largest national park of Madhya Pradesh

59) D

In the below image, I've marked numbers for easy understanding. I've also hand-written/drawn for your easy understanding.

To learn more on solid manipulation and unwrapping/wrapping, learn here

60) C

Know about Indian state dances 

61) A

Check the below image

62) A

Check this post on how to solve such question - working with geometry

63) A

64) A

I think drip here means Painters.

65) B

Words are written on paper

66) A

Sleeves rolled, and 'theatre of give and take' is a profession not related to teacher, pilot or even traffic police

67) A

burps mean - a noise made by air released from the stomach through the mouth; a belch.

fart - gas released from stomach. 

So, stomach is the best fit

68) C

The strange clock matches time at 12 noon. 

Given that the hour hand moves half the speed. So, at 4'O clock, it must be 8 hours. 

Also given that the minute hand rotates 6 times than usual. In other words,

in 1 hr no. of ticks of the min hand = 60*6 = 360 ticks

So, let's put like

1 hr = 360 ticks

In the given image, the min hand is at 6, which means 30 ticks 

360 ticks = 1 hr

1 tick = 1/360 hr

30 tick = (1/360)*30 hr = 1/12 hr = (1/12)*60 mins = 5 mins

So, time is 8 hrs 5 mins

69) C

I've marked them in the below picture.

70) C

71) A

72) B

73) C

Rama  - Dharma, Kalki - destruction, those two are sufficient to answer the ques

74) C

As far as Iknew, L (one famous art) represents expressionism. You can check art/painting history in resource page

75) C

Not very sure, just took from the answer key

76) C 

77) C 

distance is shown as AB in the below image.

78) D

Below image gives the explanation

79) A

The figure below shows the movement of the star in every step. Note the numbers 1,2,3....8, they represent the successive steps. In every step, the star moves diagonally till it reaches the diagonal end, after which it reverses its direction. So, the position of star should be as indicated in 8th step.

Similarly, below image shows the movement of the triangle. Note that unlike star, the triangle moves row wise and in every row, it moves two grids clockwise/anti-closkwise as represented by the second table in the row. So, in the question mark table, it should be on the grid marked in the second table of the third row. 

Similarly, we can figure out the movement of the circle. It's easy to note that the circle moves clockwise direction (one grid) in the direction indicated by no's 1,2....8

So, the position of the circle in the question mark table is indicated by the arrow in the 8th table.

80) B

Obviously.

81) A

82) A

Below image shows how the view will be constructed. Green lines are projection lines. and the actual top view is shown in red.

Why did I get a circle?

Well, if you observe the dimensions, the eliptical solid is 11 units out of which 6 units is overlapped with the cuboid. So, 5 units is overlapped. The cross section happened such that it is slightly less than 5 units, but because it is slanted, the length along the crossection is large, more than 4 and hence it could be around 5, so 5X5 cross-section of a curved surface (a circle) must be imagined. 

83) B

Just like in Q79, we try seeing a pattern from the given set. As you can see, no. 7 is moving anticlockwise one step. So, the position of 7 must be as shown in the table 4. Now, fortunately, only one option suits.

84) A, B

85) A

The flat surface marked in the image below makes it look like a sharp edge in top view. Had the case it was slanted, then the answer would be B.

Answer key to UCEED 2017 Previous paper

You are here Solutions >> UCEED 2017 solution

You may download UCEED 2017 question paper here 

 

Detailed explanation to some of the design aptitude questions of UCEED 2017 are available in the below set of videos

Answers for UCEED 2017 Exam paper 

1) 12

Out of the all 6 surfaces of the given cube, it is given that three surfaces are green while the rest three are orange. 

We are interested in finding the edges which have contact with one orange and one green surfaces,

The following image shows for one corner (top). As shown, although it has four small cubes at the top, the two edge cubes on either side will have two surfaces having a single color and another surface having another color, so they shouldn't be counted. So, for one edge, we have 2 cubes.

Now, the trick is to count the no. of such corners possible. Below figure shows all possible corners that lead to the required. All the invisible surfaces in the below image are green color. 

As can be seen, we have 6 edges, thus counting to 6*2 = 12 cubes

2) 25

Below figure shows the reflected image. The problem can be split to counting of no. of squares and the no. of non-squares (but rectangles).

Below two images gives the situation of no. of squares, which will ocunt to 6 + 4 = 10 

Below four images shows no. of non rectangles which will count to 5 + 5 + 3+ 2 = 15

Total = 10+15 = 25

3) 7

In the below figure, I've numbered each parts from 1 to 5.

In the below image, I've arranged them (based on by matching the zig zag tooth of each part, starting from part 1). If you observe zig zag tooths for part 1, has 9 depressions and a close observation of part 3, reveals that that too has 9 projections on its left side. Like wise matching each part, I ended up in the below image, now count the no. of outer surfaces. 

4) 28

Below image highlights the possible different symbols

5) 11

In the below image, I've underlined the different identified fonts

6) 7669

if we see the difference of the purchase, it will look something like below

(301-151)=150

(601-301)=300 

(1201-601)=600

(2401-1201)=1200

(4801-2401) = 2400

so, the increase in purchase range in each step is 

150, 300 (150*2), 600 (300*2), 1200 (600*2), 2400 (1200*2),

They are in GP.

150, 300, 600, 1200, 2400, 4800, 9600, 19200, 38400, ....

So, our required purchase amount false in 9th step, because at every step, max is double the difference, for example for the first step, max ~300 which is 150*2

checking the discount,

19= 30-11

49= 60-11, 

109=120-11, 

229=240-11,

469=480-11, 

the next five terms will be

480*2-11 

960*2-11

1920*2-11

3840*2-11 = 7669  

7) 1.5

considering, 

one parrot as x

one fish as y

one elephant as z

then as per the given equation

x+2y=4z (1)

2x+z=y+x (2)

we need 

z = k*x

where k is the number of parrots, so we need toe eliminate y as far as possible

from (2)

2x-x+z=y

x+z=y (3)

putting (3) in (1) instead of y

x+2*(x+z) = 4z

3x=4z-2z

3x=2z

z=3/2*x = 1.5*x

eek :D, 

that's one and half parrot! 

one parrot and half more parrot! I can't see the seond parrot being halved, Hopefully, next time UCEED examiners won't be this cruel :D (just kidding)

8) 11

Following are the alphabets that can be flipped on horizontal axis

B,C,D,E,H,I,K,M,O,W,X

9) 8

I've numbered the steps to be taken by knight which is possible the least no.

10) 8

Below picture shows the numbering that I followed. 

Note that although there are several lines on each fan wing, but when the fan rotates, all the patterns appear to be following a circular line. For example, consider the pattern 5 in wing C, as you can see, it has a wave with several dots on the top and bottom of the pattern. No doubt, if they are rotated, they will result in three circular lines. But, observe the pattern 5 in wing A. The pattern is slanted from a to b. So if the wing is rotated, then that will look like a single circle of thickness ab. This thickness (ab) covers the gaps of between the three circles formed by the rotation of pattern 5 of wing C, and so the result will be only one circle. This also covers the pattern 5 in wing B. Similarly you can find the mixing and non mixing of other patterns too.

11) 17

The letters that can be visualized from figure A are 

B, C, D, E, F, G, H, L, P

So, all together, we can visualize 9

So, no. of alphabets that cannot be overlapped to fit within figure figure1 is 26-9=17 

12) 10 

No. of gears on A = 11

No. of gears on B = 8

Since second gear has 8 no. of tooth and considering the complete 8 no. of gear movement as 1 turn, we mark on A whenever 8 gears are counted just like in the first image of the below image. Since gear A turns clockwise, we need to count the gears in the counter clockwise direction, which is the direction in which gear B mesh with A. Note the location of the 8th gear teeth. 

In the next turn start from the next teeth of the marked gear (as shown in the second image) and count again 8 gears. Repeat this until the 8th gear is on the red mark on A.

Note: I just showed images for easy understanding, not to scare you :P You can use ur pen or pencil or even your finger to count in counter clockwise and keep counting each 8 gears as 1 turn. Repeat counting mentally until the red mark is reached. 

13) 10

below image shows the triangles marked in colors, just to differentiate from each other. I wish the question could have been much clear anyway :P

14) 3

Given, at each second, the numbered disc rotates two numbers in anti-clockwise direction while the cut-out disc rotates 1 no. in clockwise. So, relatively, for every sec, the numbered disc moves 2+1 = 3no.s, assuming that the cut-out disc is held stationary.

So, after 5 secs, the no. should have been moved 3*5 = 15 times in anti clockwise direction. So, taking no. 8 as the start/refernce, move anticlockwise 15 times which will give the required no. which will appear in the pentagon after 5 secs. 

15) 0.715

First, find the area of the black area, then find how much area it is occupying with respect to the total area, that ratio will give us the probability 

Total area = 2*2 = 4

Area of the white circle without black square in the center 

=  (PI/4)*sqyuare_root(dia)

= (3.14/4)*4 = 3.14

to find the side of the inside sqaure, not that one of the hypotenuses of the triangle is itself the diameter of the circle as shown in the below image. saying the side of the square as a and using the pythogerous theorem

square(a) + square(a) = square(d) = 4

2*square(a) = 4

square(a) = 2

a = square_root(2)

So, area of the inner square = a*a = square_root(a)*square_root(a) = 2

So, finally, area of the black part = total area - area of circle + area of inner square = 4-3.14+2 = 2.86

The required probability is = area of black divided by total area = 2.86/4 = 0.715

16) 0.625

Total no. of summing combinations possible are 4*4 = 16

Total no. of combinations for the sum is 

considering only 5 in the first circle and matching with all the four no's in the second circle

(5,2), (5,3), (5,4), (5,5)

doing the same for the other three no's 2,3 and 4, we get the combinations

(2,2), (2,3), (2,4), (2,5), (3,2), (3,3), (3,4), (3,5), (4,2), (4,3), (4,4), (4,5)

out of all the combinations, the combinations which add up to 7 or more are

(5,2), (5,3), (5,4), (5,5)

(4,3), (4,4), (4,5)

(3,4), (3,5)

(2,5)

which are 4+3+2+1 = 10

So, the probability is 10/16 = 5/8 = 0.625

17) 36

  

no. of surfaces from left = 7

no. of surfaces from front = 7

no. of surfaces from right = 5

no. of surfaces from back = 5

no. of surfaces from top = 7  

no. of surfaces from bottom = 5

For a clear understanding of how to count - check this link

For your understanding, I've shaded the first solid so that you can get a clarity of which part belongs to solid and which isn't. 

18) 55

Since they reach their home 10 mins early, it means the time saved by her husband to travel the distance (equal to the distance walked by her) to and fro, should be 10 mins, 

So, the one way travel time for her husband is  5 mins, but she started 1 hour ago to reach the spot. So, time taken by her = 60 min - 5 mins = 55 mins

Further explanation:

Above image shows the situation. It is clear that Sharmila's husband pick up her at the bust stand exactly at 6PM. Let's say it takes 't' mins for the car ride to reach their home, everyday, from the bus stop. So, they will reach home everyday t mins after 6 every day. This is when they start at 6PM at the bus stop. 

Now, today, since Sharmila had already started walking and let's assume that her husband pick up her at say C. This time is going to be lesser than 6PM. That's because, if it was 6, her husband would have already been reached to the bus stop. So, they met before 6PM. Since they need 't' mins to reach home from bus stop, her husband needs the same 't' mins usually to reach the bus stop from the home (during  the on ward travel). So, as he reach C and saw her wife there, he had saved time to reach the bus stop (from C to bus stop) and also he had saved the time to travel from bus stop to C, which whole together was given as 10 mins. So, half of the time (10/2 = 5 mins) is needed for her husband to travel from C to bus stop (since the total saved time due to onward travel from C to bus stop and also the return from bus stop to C is 10 mins). So, they actually met 5 mins before 6PM, which is 5.55PM. Since Sharmila started at 5PM she travelled 55 mins before she saw her husband.

19) 15

Below image shows the rules given by 1,2,3,4,5

and the below table shows the possible arrangement. 

20) 10

AB is equal to the radius of the sphere which is 10m

Explanation: 

If you see the second image below, given a cuboid or any box structure, if you join the opposite corners (usually called as the diagonals) then they are going to be of the same length. Which means in the second below image, diagonal OC = diagonal AB.

Now, if you check the first image below, the given red line joining A and B will be of the same length as the other diagonal OC. Since O is the center of the sphere and OC is nothing but the radius of the sphere, AB = OC = R (radius of the sphere)

21) A, C

22) B, C, D

The following are non effective considering rural illiterate scenario

I, II, VII 

23) B, D

24) C, D

25) B, D

26) A, B

27) A, B, C, D

28) A, B, D

By careful observation

29) A, B, C, D

All the patterns in the option can be used. 

30) C, D

Below figure shows the impossible options

31) A, B, C

Below image shows the explanation with numbers marked, only D doesn't follow a pattern.

32) B, C

33) A, C, D

34) A, B

35) A, C, D

36) A,C,D

Except for B, all the remaining parts are needed.

37) B, C, D

The + and - should be aligned in the same direction if there are multiple batteries and they are connected in parallel. So, clearly circuit S will not glow. 

Batteries in series (one next to another) as shown in Q, will provide double the energy and so they should glow more, Unlike in parallel batteries which provide only half the energy each. So, R is same as P since parallel battery of 2 no's equilvalent to one batter as in P.

38) A, D

Numbering the different colors as shown in the below image.

I've marked the arrangement which is possible. They are obtained by folding the given unfolded shape into the paper, rather than folding up.

39) B, D

It's obvious since they said that when the force was removed, it gets back to its usual position which will happen only when there is some springing action. A and B, doesn't provide spring support, while B is similar to safety pin design and D is obviously a springer model, both of which obviously provide the return action.

40) A, C

As you can observe in each column, the no. of circles in each box decreases by 1 from top box to the bottom box and the no. of triangles increases by 1 no. in each box. Below image shows the explanation for the first column (three boxes), likewise if we do the same thing for the last colum, we note that the top box has 5 circles, and 1 triangle and the bottom box (on the same column) has (5-1)=4 circles and (1+1)=2 triangles

So, the final box should have

4-1=3 circles and

2+1=3 traingles

41) C, D

42) A, C

Exposure is same in all the three cases and the first thing varying is the focus. Image from moving camera should have equal effect on all the parts of the given photo, while aperture size will have effect on parts of the given image.

43) A, C, D

44) B, C

Both suits the purpose. 

45) A, C

Not sure, I just googled it

46) D

47) A

48) A

Clearly, the emoji move left to right such that its tongue is out alternatives. So, the emoji in the ques mark should have tongue out. And the two kind of emojis (with tongue out, alternates in each row.

49) B

Just unfold R, in the reverse direction, marking all the patterns as shown in the below image

50) D

Definitely, S should come next to P, because by matching the top circular white space in both. Only option B and D have that. Matching P, left side and R right surface, it gives a correct match.

51) C

Observe the bike, alternates in direction everytime - left and right. So it should be left. The pencil increase in size in every step. Sandals pair move in anti clockwise direction, slightly more than 90 degrees in each step. Clock color, changes according to elementary color pattern, orange-yelloe-green-blue

52) A

Clearly, the alphabet no, is equal to the no. of sides of the given shape.

Like the first triangle has 3 sides and the alphabet C, appears in 3rd number in the alphabets list. Similarly F = 6, H=8, and the fourth pattern has two shapes, one 8 sided and one four sided, so HD, 

Last pattern has only one shape which has 8 sides, and so It should be H again.

53) B

The logic for this is involved. But, let me put this way.

oberving the clocks, we see that the second and clock has remained in the same position as firsts. So, it is eithr making o progress or 12 hrs advancing. 

the third clock shows 3'O clock which mean it has advanced 6 hrs from the second clock. And he fifth clock shows 4.5 hrs

So, putting them as series, we see

12, 6, ?, 1.5 

6 can be looked as 12/2

similarly when we look ? as 6/2 (=3), then we see that ?/2 which is 3/2 = 1.5, which agrees with the last clock. SO ? should be three hours from the previous position

previous clock (third clock) is 3'O clock so, the answer should be 3+3 = 6'O clock

54) B

In the below image, I've marked some numbers, a line and stars. The red line denotes the center of rotation. Each orange dots to the right of the center red line X-X when rotated 180 degrees anti clockwise in the top view, will form semi circles on the top.  

Similarly, each orange dots lying on the left of the center red line X-X when rotated 180 degrees anti clockwise in the top view, will form semi circles on the bottom.

Also the numbers dots will hence form a circle, like marked in the image, number 1 on the right of X-X axis will form a semi circle on the top, while number 1 on the left of X-X axis will form a semi circle on the bottom, both together will form a circle. All the numbered dots will hence form circles, only the blue star on the right side of X-X, will make a semi circle o the top, while the blue star on the left side of X-X will make the outer semi circle o the bottom as shown in option B

55) A

A fits figure 1, when A is made upside down and matched with figure 1.

56) B

Here, I'm trying to give a detailed explanation for your easy understanding. 

Let 

mass of cuboid = x

mass of sphere = y

mass of cube = z

mass of cone = p

Given,

x+y = z+p (1)

x = y+p (2)

y = 2 (3)

using (3) in (2)

x = 2+p

p = x-2 (4)

using (4) and (3) in (1)

x+2 = z+x-2

which gives

z = 4 

also given that

2kg mass is equivalent to 62.5 cubic cm of volume,

so, z=4 kg mass is equivalent to 62.5*2 = 125 cubic cm

Now, the size of the cube can be obtained by equalling the volume of cube to 125

a*a*a = 125

a = 5,

also given that length of the cube doubles when exposed to air.

So, now the size of the cue is 10X10X10

Let K no. of cubes are required 

volume of the tank = K*voume of each cube

50*50*50 = K*10*10*10

so,

5*5*5 = k

k = 125

57) A

Right side view says that there's the white strip to the left of the top view, 

Left side view says that there is no white strip on the top portion of the left side view and so in the top view also, there shouldn't be any white strip to its left. 

Similarly, front side view shows that there's the white strip in The mid of the top and so in the top view, the bottom part of it should show the strip

58) B

Blue strip in all the strips are in contact with 3 other color strips except in B which has only 2 contacts.

Similarly violet color in the given pattern are in contact with three other colored pattern, except in B which shows 4 contacts.

So, B should be odd.

59) B

Based on the size of the red counter, and noting the curves of 'b' in the questions, P in option B seems more reasonable.

60) D

By observation

61) D

Current time in the question is 1.40

adding 8.45, we have 10.25, which will look like as shown below.

It, when rotated 270 degree, will like the one shown below

62) B

given 10% is one lakh in 2001,

so, 100% is ten lakhs in 2001

Population in 2011 is 10% increased. So, the total population is 11 lakhs.

Percentage of public vehicles = (5 lakhs/11 lakhs)*100 = 45-46%

So, the percentage of private vehicles = (2 lakhs/11 lakhs)*100 = 18%

63) C

64) B

65) A

  

i. If we rotate the pattern 18 degree, we will get the pattern as shown in option A

ii. If we flip horizontally, then the pattern will look like B

iii. If we rotate the pattern in ii by 180 degrees, we will get a pattern as shown in D

iV. If we flip the pattern in iii, we get pattern shown in A

66) C

Q rotates anti clockwise, R roates clockwise, S rotates counter closkwise, T rotates clockwise and U rotates counter-clockwise.

67) D

68) A

69) B

70) C

71) D

72) C

73) B

Below image shows the partition

74) C

When two bolts mesh, they should rotate in opposite direction. So, since the two bolts are rotating in the same direction, they will remain the same and will not move

75) A

Cutting initi start at X, and so the strength should be more at that point

76) B

Below image, I've marked the symbol.

77) A

Below image shows the pattern.

78) C

79) B

A pin hole camera will capture the surface upside down and, right to left and vice versa.

80) D

81) C

82) C

Below image shows the possible path, starting from idi

83) D

84) C

C's top abd bottom surface persepctive are not in line with the rest 1 point persepctive

85) C