CEED 2023 Part A answers with detailed solutions

 CEED 2023 Solutions.......very detailed !

 Stuff You Look is now in Instagram 😊💥 - stuff_you_look

This page is best viewed from web browser !

1) 8

The situation is shown in the first image below, which represents the top view of the pentagonal building. A,B,C,D,E represents the watch tower where the guards are supposed to stand and observe the walls. A guard at watch-tower 'A' can observe walls 1 and 2. Similarly, a guard standing at say tower D can watch walls 3 and 4 (adjacent walls) and so on. Considering this pattern watch guard at each tower can just watch two walls. So, in this case each wall is being watched by two guards. If you are still not sure of how this is so continue reading this para or jump to the next para.

• Wall 1 can be watched by person at A and person at B
• Wall 2 can be watched by person at B and person at C
• Wall 5 can be watched by person at A and person at E
• Wall 3 can be watched by person at C and person at D
• Wall 4 can be watched by person at D and person at E

Now, if each wall has to be seen by at least three persons (as asked in the question) Let us see one of the best possible way (out of few other possibilities). Let's say two guards a1 and a2 are at watch tower A, then wall 1 can be seen by both of them. We just need one more guard for the wall 1 to be seen and so let us assume that only one guard b1 is sufficient at B. Now, wall2 is observed by one guard (b1) at B. We still need at least two more guards for the wall2 to be seen. So, we need two guards at C and let's name them c1 and c2 as shown the second image. Continue this pattern and you should be needing one guard at D, two more guards at E. Total minimal guards are therefore just 8.

 

2) 13

For the piece 10 to move to position X, there are many possible ways. Four possible ways are shown as 2(a), 2(b), 2(c), and 2(d). These are the possible shortest paths.

let us try to analyze how many steps are required to move 10 to X as per the path shown in 2[a].

The trick is to start from the empty position (X) and move piece such that the required piece (10) shall be moved towards the position X, as discussed below.

• move 9 to X, which will create empty space (X) at place 9.
• move 5 to previous 9 position (9 is empty due to previous move)
• move 7 to position 5
• Now move 10 to position 7 (which is empty due to previous move step) 

This will look like positions as shown in image 2[b] with total 4 steps so far

Now, let us move number 10 to one step ahead, to position 7. For this do the below steps (also shown in figure 2[c]

• move 8 to X
• move 7 to 8
• move 10 to 7

This will create an empty position at position 10 as per fig 2[c], which is shown in fig 2[d]. Total steps so far are 4+3 = 7. Let us now move number 10 to position 5 by following the steps shown in fig 2[d].

• move 4 to X
• move 5 to 4
• move 10 to 5

This will create an empty position at position 10 as per fig 2[d], which is shown in fig 2[e]. Total steps so far are 7+3 = 10. Let us now move number 10 to position 9 by following the steps shown in fig 2[e].

• move 12 to X
• move 9 to 12
• move 10 to 9

Total number of steps needed for the entire moves are 10+3 = 13.

3) 16

I usually follow the pattern of identifying the number of shapes without any collision and then step by step identifying the other required shapes that are colliding with the other part of the shape. In the first image, I’ve highlighted the triangles that are not colliding with any other part of the image. For similar questions, which needed different method, I would go by either left to right and then top to bottom….to count the shapes. The method that I choose depends on the complexity of the image being given.

Following this pattern, the number of triangles that are directly visible as shown in the first image are 9. Now in the second image the number of identified triangles is 6 as shown. For your understanding I’ve shown some triangles as dashed and some as solid lines no in the third image I’ve highlighted the leftover triangle. Totaling to 16.

4) 3

In the first figure I’ve shown the planes (at 1/6^th and 1/2th) as mentioned by the question in three directions. I’ve shown dotted lines with different colors to indicate the cuts. Assuming the total cube side as 6, the first cut will be at length 1, second at the mid (length 3) as shown in the first figure.

Considering row 1 I’ve highlighted the blocks that can be obtained by the cutting planes. I’ve also listed the blocks based on their dimensions. Only one block turned out to be a cube of dimension 1x1x1

Similarly in the second figure, I’ve shown the obtained blocks for the second row with depth as 2. Only cube is possible with dimension 2X2X2.

In the final figure, again only one figure is possible with dimension 3X3X3. Note that for explanation I’ve shown all these figures but during exam I would try to imagine the cuts and identify only the cubes with all dimensions same. And it is obvious that we can expect only one cube of each possible dimension (1, 2, and 3)

5) 20

According to the given first condition, Robert can buy either 50 apples or 40 bananas with his monthly allowance. Let the allowance be X. Let the price of each apple be ‘a’ and the price of each banana be ‘b’. So,

X = 50*a (or)

X = 40*b

Which mean, (here * means multiply)

50*a = 40*b

40*b = 50*a

b = (50/40)*a

As per the question, one month he decides to save 10% of his allowance, which mean he is going to spend only 90% of his regular allowance (90/100*X = 0.9*X). Out of which he already bought 20 bananas.

If he only has to buy Bananas, he could buy 0.9*40 number of bananas, which is 36 bananas. That’s because the price of the apples or bananas ae going to be the same and only the quantities are going to reduce due to reduced budget/allowance. since he bought 20 already, he could only buy 16 bananas (out of 36 bananas) with the leftover savings

16*b = 16*(50/40)*a = 20*a

Which means he could buy only 20 apples (which his equivalent to 16 bananas) with the leftover allowance.

 

6) 42

This is not a difficult question to solve if you understand something I call ‘surface continuity’ which means the continuation of a surface if it is curved. Let us take the first alphabet and explain this.

Considering letter ‘D’, observe the edges (as shown in the top view) carefully. Even though the alphabet seems to have edges (a,b,c,d,e, and f) they can actually be treated as continuous. So, I count the outer surface as 1. In the next figure I’ve mentioned the possible surfaces (p and q). Again, q is continuous and so it is counted as 1. For Alphabet D, total no. of surfaces including the first and second figure of D is 1 + 1 + 1 (this is without counting the top surface)

Similarly, for the other alphabets I’ve marked the surfaces

For E, side surfaces count is 11

For S, side surfaces count is 4

For I, side surfaces count is 3

For G, side surfaces count is 6

For N, side surfaces count is 9

Apart from this, each alphabet in the top will have one surface (D, E, S, I, G, N) total top surface count is 6

Therefore, total surface count = 3+11+4+3+6+9+6 = 42

 

7) 13

There are total 4*4 = 16 number of Q letters. I will just identify the repetitions and eliminate those no. from the 16 to make it easy for me. By observation I’ve highlighted the repetitions (in different color) for your understanding. Now, I can remove those repetitions to get 16 -3 = 13

Tip: first observe the tail to see similarity/difference. Then you can observe the width of O to see if the fonts are different even if the tails appear to be same.

 

8) 2

First, we need to find the radius of the rotating pin-disk. The ide is simple. We need to know the circumference of the small rotating circular pin-disk and also the circumference of the bigger circle (having radius 10cm). Then The circumference will help in knowing how many times the disc has to rotate to complete the circle. If you are not sure, what do I mean by Circumference, refer my video on ‘basic math for design exams’.  Circumference measures the total length of the circular line and so the idea here is we need to know how many times the total length of the disc circle coincides with the total length of the big circle as the disc rotates. These solutions are prepared by Bhanu Chander and copyrights to Stuff You Look blog. If you see these solutions in any of your coaching institute material then it shows how degraded your institute is. They should be ashamed of copying SYL content just to make money.

As shown in the figure, we need to find R first, which is side AC, given side AB and 30 degrees. The calculations are shown in the below figure. We get R=5cm

Circumference of the bottom big circle with radius r=10cm is 2.PI.r = 2*3.14*10 = 62

Circumference of the rotating disc with radius R=5cm is 2.PI.r = 2*3.14*5 = 31

Now, Let us assume the pin-disc needs X turns to complete. So, X*31 should be greater than 62. Which mean

X*31 > 62

X >  62/31

X > 2

So, the pin-disc should make atleast 2 turns to make a complete circle on the base circle.

9) A, B, C

Let us assume the two cuts as R for rectangle and T for triangle as shown in the first figure.  The next two figures explains how I was able to identify the cut shapes. 

10) A, B, D

The ide is simple. You need to observe the movement of the end marked as B with the push at end A as shown in the first image. As show in the second image, in both the options A and B, when we step/press at A, due to the mechanisms, they tend to push the knob of the sanitizer as shown by arrows and hence they can work. In the next image, shown as option C, when we press the end A, due to the pivot at the bottom the entire mechanism will try to raise up and hence the sanitizer will not work. In option D, when we press the knob, and since there is a pivot at P, the mechanism will try to lower at B as shown by arrows in the third image. Thus, the sanitizer will work.

11) B, C

A is wrong because specific elements are arranged in a repetitive manner. For ex. 72 beats every minute, 6 degrees every min, structure consisting of SERIES of beams and nodes.

D is wrong because scales are indicative of time but not volumes

 

12) C, D

Before inspecting the options, I wish to explain the basics so that it will be easy for you to solve similar kind of physics related problems.

Assuming you are trying to sip juice from the bowl as shown in the first image using a straw. For explanation purpose I’ve shown a thick straw of higher diameter but practically we will be using a thinner straw (small dia). As you start sucking air, mentioned as 1 circled in the figure shown, you have removed the air inside the space of the straw. As you continue to sip and since there is no air left vaccum will be created inside the straw with zero pressure, marked as 2 in the figure. Since the pressure at this specific location is lower than the outside pressure, the atmospheric pressure shall try to push the liquid down and acts all along the surface area of the liquid that is exposed to the atmosphere. This is shown as 3 in the same figure. This higher pressure (compared to zero pressure in the straw) will make the liquid in the straw raise, making it reach to the end of the straw and hence you will be able to sip the juice. 

In option A and B, since the junction J is above the surface (AB) of the liquid no matter how much try to sip by sucking air the liquid will not raise. This is because air from the side straw will be sucked as shown in the figure 2. In options C and D, the junction J is below the surface of the liquid and hence whenever we sip through the straw the juice will be sucked as the straw is not connected to the secondary straw through which air can be taken like in option A and B. Note that in option C, the liquid will be sucked only till the liquid level falls in line with J. After that the side straw gets connection to the main straw and hence air will start sucked from the side straw, making the juice undisturbed.

13) A, B, C

I don’t think I’ve to give explanation for this question as it is straight forward (the rotation thing). Anyways, here are a few tips for you to solve this question.

135 degrees anti-clockwise is same as 45 degrees (180-45) clockwise given that the given pattern is symmetry and replicates the same pattern if we rotate it 180 degrees.

90 degrees clockwise is same as 90 degrees anti clockwise and after 90 degrees clockwise or anticlockwise, the patterns coincides and so it will look the same in top view (check option C)

14) A, B, C, D

 All the stake holders are required to be asked for feedback but the order of importance should start from the user and the end user should be given the highest priority whenever we make designs or products. If you ask me, I will give the following order of importance (I might be wrong, but I strongly feel the below order based on my experience)

• Existing user,
• customer support,
• People who deliver food,
• Employees who offer food

 

15) A, B, D

I’ve shown in the figure how I’ve arrived at the required image for the possible options. Follow the numbers 1,2,3 for the correct order of obtaining the completed image

16) B

Let us mark the pin as P as shown in the first figure. Even if we rotate the disk as indicated by the red arrow, the whole arm might tend to angle but this will not affect the position of the purple metal bar.

In option B, if we turn the disc such that Pin T is now T’ after the slight rotation, the position of the connecting slider, denoted as PQ will be P’Q’. This mean the entire purple metal slider will be able to move. Let’s say we mark points R and S before the rotation, they will be at R’ and S’ respectively after the rotation. This mean the bar is making a linear motion.

Option C is somewhat similar to option A, where even after the disc rotates to some degrees as shown in figure (from a-b to a’-b) only the connecting rod in brown color will turn while the connecting end at b will mostly stay at the same position.

In option D, the contacting point at P will remain at the same location (P’) even if we rotate the disc (say point a moves to a’)and this will not at all affect the position of the point P or P’ on the purple colored metal slider. This mechanism will not work.

17) B, C

A is not possible because the curve should be deep. In the following figures. I've drawn and shown how the cam (non-cylindrical) rear wheel is causing extra projection/curvature. Note that due to the shape of the rear cam/wheel, the curve traced by the pencil is deep.

18) A, D

I think the answers are straight forward because it is a simple rotation inspection question. Still, I will try to give a quick hint on how to identify the correct options. I’ve marked the directions (which I usually follow). Option A is the rotation view of the given image. Visualize the backside view of option A and flip it horizontally (upside down) and you will be able to see the front view of the given object.

Backside view of option D is the front view of the given object. (These whole solutions are the work of Bhanu Chander of Stuff You Look. If you chanced to see these solutions in any other platform like in your coaching institute’s study materials then they have simply copied from SYL blog. Now you know how genuine they are). In the next two figures I’ve given explanations of why they are not the rotated views.

19) D

I think most of you would’ve answered this already. Regardless I will share my thoughts on this. When operating with right hand it is easy to reach the lower right portion of the keypad. Orange is the first easiest to reach, followed by green. However, since it is a small key we consider red as the next easiest key to press followed by green. Blue is the least easy key to operate with right hand.

  

20) D

I would solve this question by looking at the lengths ‘x’ and ‘y’ as shown in the figure. The length x is slightly greater than or equal to the length y. Considering this requirement option A and B are definitely not the correct ones. Out of option C and D, I would look for the correct pattern of ‘p’ and ‘q’ portion as shown in the second figure. In option C, location p has a solid instead of empty. Hence D is the correct option.

21) A

Teak is a hard wood. It is strong and durable, able to withstand extremes of heat and cold. It is very versatile material. It has many applications including building construction work, interior and exterior furniture, doors and window frames, flooring, deck decks and the like. An outstanding feature of teak outdoor furniture is the ability to withstand all types of weather. It is one of the few woods in the world containing a natural oil which repels water, keeping it from warping, cracking or becoming brittle. Teak wood can be carved by hand to create more intricate furniture.

Hardwood plywood is a great choice for furniture, cabinets, and many other projects due to its strength, stability, and convenience. Plywood is High impact resistance, High strength to weight ratio, Environmentally Friendly, Durable, and Cheaper than Solid wood. Not always easy to sculpt on this. Without some special resistance method maximum after long-term get attacked by insects.

MDF is a softer material than plywood and tends to sag or split under pressure. MDF doesn't handle moisture very well, either, so it is more suited for indoor use, such as in furniture. is generally cheaper than plywood. MDF board would be the best option if you want a low budget and material for interior application. If you want material for an exterior application that can withstand moisture, then plywood is the best option.

Particle board is cheaper, denser and more uniform than conventional wood and plywood and is substituted for them when cost is more important than strength and appearance. IParticle board is cheaper, denser and more uniform than conventional wood and plywood and is substituted for them when cost is more important than strength and appearance. Not ideal for heavy-duty use. The disadvantages of particle board include its susceptibility to damage, lack of water-resistance, and its incompatibility with drilling (so, cannot handle screws)

22) A

Since the zoo keeper got the information that 7 animals have escaped and out of that he deduced that atleast one baboon would’ve escaped – it would mean that the number of monkeys would be definitely less than 7. Only then it is possible for him to assume that one or more baboons have escaped. Looking at the options, y should not be more than 6. A is the impossible option then.

23) C

The Blue Period is a term used to define the works produced by Spanish painter Pablo Picasso between 1901 and 1904 when he painted essentially monochromatic paintings in shades of blue and blue-green, only occasionally warmed by other colors. Below image taken from Wikipedia is one example of Pablo’s ‘The Old Guitarist’ painted during the blue period, the period when he was in depression and was using mostly blue and blue-green shades.

For a detailed study on types of color themes refer the below two websites:

The 6 Color schemes - 

Color Theory 101: A Complete Guide to Color Wheels & Color Schemes - 

24) A

 As shown in the figure, face ‘a’ will be turned when we try to unwrap it. So, whatever the printing (top part of ‘Marker’) will not appear in the unwrapped front portion of the paper format shown in the options.  And in the unwrapped view of the page the ‘b’ portion will be the first to be visible from the top as marked in the figure. Based on this, only option A is seen to fit.

25) C

I feel task 2 and 3 should be on the same height while washing utensil shall be on a different height (usually lower height)

26) C

First, I will try to see if by using the given options, will I be able to draw a vertical line, which is required to complete the fish, and if yes, then will the tracing and replication be possible between blue and red?

The triangular link as highlighted in the figure for option A will make it difficult for the mechanism to achieve the goal. In option B, if x and y are of same length then there is a possibility for the fish to be traced. But the traced fish would be of the same size.

Option C is a very famous mechanism and the beauty of it is that it can help in drawing straight lines (esp. vertical line) using the ends (blue and red ends). Option D is uncontrollable and even if we move blue end most of the times red end won’t respond and there is not proper connection between the two links. This is not a good mechanism. A good mechanism should enable you to control the movement of an end as per your needs and as you expected.  

27) C

We want to find the pattern after one and half hour, which mean after 90 mins. Given

In every 15 mins dial Q rotates by 90 deg clockwise, and

after every 30 mins dial P rotates by 45 deg anti-clockwise

In 90 mins,

(Since 90 mins = 6 times 15 mins) Dial Q rotates by 6 times 90 degrees (540 degrees) clockwise. This 540 degree can be taken as one complete turn/circle (360 degrees) and 540-360 = 180 degrees turn, the shape of which is as shown in option A.

In 90 mins,

(Since 90 mins = 3 times 30 mins) Dial P rotates by 3 times 45 degrees (145 degrees) anti-clockwise. Which mean 45 degrees clockwise. If we rotate P by 45 deg clockwise it will look like the shown figure. Now, if we overlay the rotated view of Q (which is shown in option A) on top of the rotated Q shape as shown in the below figure we should be able to see option C.

28) C

First of all, stacking mean placing chair on top of chair when the chairs are not in use. Stacking is possible only when the width of the supports (shown as ‘x’ in the figure) is higher than the width of the seat (shown as ‘y’ in the figure). In all the options the width ‘x’ is either same or higher than ‘y’ and hence stacking will be difficult. This is in mathematical terms, so let me put it in simple language. The backward legs should be slightly protruding out of the seat, only then we can make another chairs seat to stack (else there will be no space to make it sit due to the chair legs interruptions). I hope you are able to visualize and understand.

29) B

Egg and sugar and two separate elements and will go into making cake. Option A suits this where the two small hexagons are representing egg and sugar individually and the larger hexagon represent the cake, which holds the two elements.

Because of seed came tree and because of tree came fruit. And this is represented by option D (small shape inside a medium sized shape and medium inside a big shape)

Rock, paper, and scissors are three contrasting objects and hence option C suits, as the three shapes are shown no relation between them.

Option B is weird as the two small shapes are shown intersection (union) which is not indicated by any of the three given relationships.

30) A

Looking at the options I feel the circles meant the owner of the dog (the sisters) and the triangles represent their dogs and the scribbling represent the movement of the dog and their distance. Considering this hypothesis, as per the given instruction, the elder sister (bigger circle) should be at the center while her dog (a triangle) should lie near to the bigger circle. The middle sister (the medium size circle) should lie inside the fence along with its dog, and the younger sister should be outside the fence with its dog little far from her as compared to the distance of the scribbling of the middle sister (given that her dog is running and chasing squirrels)

31)

I’m kind of lost in understanding what is happening with this question. But I tried my best to list about the details of the info that these paintings carry. Below set of figures should give you some info.

32) C

Scissors shown in option D is not meant for breaking nuts. A is the worst design as the pressure applied to the nut is very minimal given that the handle are very close to each other. The more the distance of the grip end from the pin p (shown as x) and the more the end-to-end distance (shown as y in the figure) for the user to hold the better will be the cutting pressure. Plier shown as option C provide greater pressure, followed by option B.

33) B

What I know is when a camel gets up from its seating position it generally uses its right front leg first before using the right left leg along with the hind legs. Keeping this in mind I could see only option B where from 1 to 2 the direction of movement is towards left. From 4 to 8 it rightly indicates the movement from left to right.

34) C

Considering green circle with no straight sides as 0, triangle with three sides as 3, rectangle with four sides as 4, pentagon with five sides as 5, and finally six side hexagon as 6.

Now, sum the number of sides in every row or even column. Like in first row, we have

1 hexagon + 2 rectangles + 1 circle = 1*6+2*4+0 = 14

Consider the third row

3 triangles + 1 pentagon = 3*3 + 5 = 14

Similarly, you can check for last row as well. It will sump up to 14. Considering this if we sum up the 2^nd row it should be 14.

1 pentagon + 1 rectangle + 1 circle + ? = 5+4+0 + ? = 9 + ?

So the ? should have 5 sides in order for it to sum to 14

35) B

Observe the distance x and y in first figure. Also, the top surface ‘ts’ is flat while the bottom surface ‘bs’ is cut slant. In options A and C, the top surface ‘ts’ are not straight and hence they are incorrect. Now, inspect the distance ‘y’ in options B and D. Option B seems to fit as y should be short unlike in option D.

36) C

The best way to solve these kinds of unfolding problems is to move in reverse on how it got folded. This I’ve shown in the figure.

37) C

This is pretty straight forward.

38) B

By observation

39) A

As shown in the figure, because of the curved surface, the reflection would look like this. It will appear upside down due to the light rays from the object.

40) C

By observation I tried to match the mirror image of the given pattern and C turned out to be the perfect match. As shown in the figure I’ve highlighted the patterns that I considered as a deciding factor, ordered by the numbers shown. These solutions are the copy right of stuff you look blog. 

41) A

As shown in the below figure, I’ve highlighted the portion of the patterns that distinguishes between the correct pattern and the wrong pattern. Highlight ‘P’ is the deciding factor in eliminating options B and D, and highlight ‘Q’ is the deciding factor in eliminating the C option. 

I hope my solutions have helped you to a good extent. Support Stuff-You-Look blog by ignoring the scam-sters who try to steal this blog's content and the solutions shared. Follow SYL in FB and Insta to keep yourself updated of the latest releases. All the very best with your start! 

Sketching Level for CEED exam

Maths Basics for Non Math students (trust me...these basics are very much sufficient for cracking CEED, UCEED and NID design exams!)

What to start for CEED exam (applicable for CEED 2024 too)