29 May 2015

Answer key to 2015 UCEED official sample question paper

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This post serves as an answer key to UCEED official mock test releases in 2015. I have tried to give detailed explanations for your benefit. You may get the UCEED 2015 sample question paper here   


UCEED 2015 sample paper answer key


Solutions :


1)


One of our friend Pyush Shinde, came up with a simple way of answering this question :

Just count the number of horizontal and vertical lines and sum them, say for T =2, H =3, E =4

Now, THIEF = 2+3+1+4+3 = 13 !

simple isn't it, thanks to Shinde for sharing this with us,

If you are satisfied with the above solution, you can skip the below method. But if you are interested in knowing other methods and if you have time, you may check the below method too!

My way (bit lenghty :P)  - but could be helpful to solve other similar questions.

This kind of problems has to be solved by assigning the numbers usually from 1 to 9 to each single letter with the following conditions

1. No two letters will have same number (letter numbering should be unique)
2. Summation is done once the numbers are assigned to letters

Some times (many times) we would be forced to opt for 0 (zero) also, at that time, we may consider assigning a unique number (between 1 to 9, including both) to the combination of the two letters, like we see for this example. Let's work out this question

Remember all the numberings for the letters T,H,E,L,I,F should be between 1 to 9 only !

Given 
THE = 9 .............(a)
LIE = 7  ........... (b)
FILE = 10 ............(c)

subtracting eq (b) from (c), we get 

(F+I+L+E) - (L+I+E) = 10 - 7

F  =3

so, we need to choose values for L,I,E which sums to 7 as in (b)
E also appears in all equations and lets make it 1
E = 1

so,
 L+I+E  = 7
 L+I = 7-1 = 6

say I choose 4,2 for L and I (if you consider 5, then the other no, should be 1, which is already taken, and we cannot take 3,3, so only 4,2 is left)

i.e L = 4, I = 2

now from (a), T+H+E = 9

T+H+1 = 9
T+H = 8

here comes the problem, since T+H = 8, they should be one of (5,3) (4,4) (7,1) (6,2) and reverse order also.

But we already chose 3,4,1,2, so none of the options is valid. So, frankly speaking, the questions has NO ANSWER !

but considering the case where we choose two letters together (by assuming one letter as zero), we could say that T+H = 8, or TH = 8

Now, THIEF = TH + I + E + F 
                    = 8 + 2 + 1 + 3
                    = 13

You may even try assigning say 2 to E instead of 1, you should get the same answer ! but only thing is again T+H = 8, considering one as zero ! If you have options that says no answer, then go for it, if it's numerical type, then consider one letter as zero and solve the equation.

2)

This question is purely based on your observation. Anyway, you can do the following steps to avoid confusion.

Follow the following steps
  1. Assign unique numbers starting from 1, to the different types of colors. 
  2. First consider a particular color say blue, and mark the unique number (say 1) to the small squares having that color
  3. Next consider another color. Now as usual assign another unique number (now 2 since one is already used) and mark the unique number in the square with that color
  4. Continue these steps until all the aquares are numbered
  5. Now note the last number, which will give the number of different types of colors.


3)

This question is also based on your observation. Anyway, you can do the following steps to avoid confusion.
  1. Assign unique numbers starting from 1, to the different types of circles. 
  2. First consider a particular circle pattern, and mark the unique number (say 1) wherever it is in the given patterned image 
  3. Next consider another circle with different pattern. Now as usual assign another unique number (now 2 since one is already used) and mark the unique number in the given image, wherever the pattern is found
  4. Continue these steps until all the 64 circles are numbered
  5. Now note the last number, which will give the number of different type of circles.

Note : same circle are shown in rotated views, consider them as same and assign the same unique number 

4) 

The situation is given in the below picture H stands for home, M for market, s for school, PO for post office.


It's given in the question that when Alakananda travels exactly north from Market, she reaches Home, and it's also given that walking from school exactly in east 37km, will end up at Market. and from market, if she move towards east, she will reach to Post office. So, School, Market and Post offcie should lie on the same straight line. 

According to the triangle formed by SHM, applying Pythagoras theorem

x = sqrt(37^2 - 35^2)

You don't even need calculator to solve this, just apply (a^2 - b^2) formula, which is equal to (a+b)(a-b)

so,

x = sqrt((37+35)(37-35))
  = sqrt(72*2) = sqrt(144) = 12

Now, according to the triangle formed by H-M-PO, applying Pythagoras theorem

y = sqrt(13^2 - x^2)

y = sqrt(13^2 - 12^2) = 5

So, distance from school to Post office = 35+y = 40


5)

The below shown picture illustrates the situation for 6X6X6 cube. Cubes which are in edges (other than the corners) will have red color on their two faces.


Consider the front face, if we were to cut the cube into small cubes of 1X1X1 shapes, then we need to make cuts as indicated by the straight lines (other than the edges) shown in the above explanatory image. For the given cube of size 6*6*6, we need to make 5*5*5. If we do so, then the individual cubes that are marked with symbols (as shown in the above examples for front side and side1) will have two surfaces with red.

So, counting the total number of cubes on corners/edges (which is 8+8+6+6 = 28 for a single side - for the present case of 8*8*8 cube) and subtracting 8 (removing 8 corners which has red color on three surfaces) will give the answer 

i.e 
(28+28+12+12)-8 = 72 cubes 


6)

The given solid is symmetry but it has slant shapes, so should be careful while counting.


Try this way -

Avoid counting the slant surfaces (rectangles in the given picture) and count the rest shapes as I have given (front-right-back-R-Top-bottom).
After this, count the slant surfaces separately.

From front (excluding slanting rectangles) -
1 small square + four triangles = 5 surfaces

The picture is symmetry, so from all sides, the same count will come, i.e
1 small square + four triangles = 5 surfaces

So, since we have to count fro six sides, so total surfaces (excluding slant rectangles) = 5*6 = 30

Now, separately count the slant rectangles - which will be 12 (be careful while counting this). So, total = 30+12 = 42

You may check the above image to get a clear understanding of the explanation.
  
7) 

Already there are 29 states (including UP - as a single state) and when UP gets divided into 4 states, we need to add three (since already one state is considered earlier). So, now total = 29+3 = 32 states

8)

If we roll a tyre/roller on flat surface, it will complete one complete turn/revolution when it rolls to a straight distance equal to the circumference of the roller.
Circumference of the given circular roller = PI*dia = PI*7 = 21.98

When the circular roller makes two rolls, length travelled = 2*21.98 = 43.96

Given, that the paper length is 40, so, the roller has to make 1 complete turn and additionally say > 3/4th of a turn but less than a complete turn, agreed ?

Now, when it makes one complete turn, number of each symbols print = 1

and when it makes one more partial turn, then Total number of symbols printed = 2 (for all the given shapes)

But for the circle, two stars are there on opposite sides, so, the total number of stars = 2+2 = 4

If it was to make two complete turns (i.e when L=43.96), then 
Number of moon symbol (which is the start) = 3
Number of all other three symbols (IT'S still) = 2 

9) 

This question is also based on observation. Since the geometry is symmetry, we can take a quarter of the symmetrical shape, and count the number of cubes, and multiply that by 4. Be careful while counting the central cubes. Better if you count them separately!

Counting this way, Answer = 11*4 + 15 = 59

10)

The below picture supports the discussion to be carried.


Let us just consider two circles (numbered 1 and 2) touching the center disc C. As you can see from the figure, the two circles makes an angle 60 degree with the center. Since, the lines joining the centers are of same length (twice the radius), the lines form an equilateral triangle (check the picture). So, the total degrees (360) with that made with the combination of two adjacent circles (60 degrees) to get 6 as the answer.

11)

M (all) ---> F (all) ---> D
M (all) ----------------> D

So, all Mammals are dolphins

Also, since all mammals are fish, obviously part of the fish are mammals, so Option A is also correct, B is wrong, straight forward. C is also logically correct.

12)

This question is also based on your observation, anyway here's a simple procedure or way of observing the image

In the given picture, consider the following next picture, with arrows, Now only consider the yellow arrows, which are exactly opposite. Note the shapes - semi circle and gun shape, now observe all the options which have this pattern. Similarly observe the red arrows, triangle opposite to a part rectangle. 


Also, don't forget the shape of the center black rectangle as per the rotated orientation of the options.

Answer : D

13) 

I'm not sure!

14)

This question is pretty straight forward

The design definitely has mass with many simple instruments, and is on earth it definitely has to face gravity, If the case is like, there's no gravity, then that device should have to float without being in contact with the ground! So, the first option is definitely wrong. 

Also, the design has four stable long bottom stand support that would support a moving/dynamic human. So, fourth option is wrong.

By visual, the design is like a globe with an performer playing from inside, so second option is correct for sure. Like they said, it's fabricated in globe form, so obviously, that demanded the designers to think for inclined and bent form of structure. So, third option might also be corect

15) 

I guess it's M, e, s

16)

All the films are Steven Spielberg hit movies 

17)

Answer A

That's why it has no/least bannet at the front!

18) 

Not sure

19)

Answer : A,B,D

20)

Answers : B,C


21)

Answer : B

22) 

It can be solved by visual observation without any hand work. If you are not able to do so, then follow the following method

Method :

Give numbering to the three rectangular projections of the given image. Three projections are there, so three numbers, follow either clockwise or anticlockwise numbering system.


Start from a reference side, say right side of the given question. Remember this reference. Now, take all the options (one by one) and try to follow the same numbering system in the same direction as done to the question. Identify where the reference side is and start from there. Visually check the distance between the number sequence in the assumed direction. If it's in correct order, then list those options.

Now check the size of the projections at each numbered mark. If it matches at all numbers, then that would be the answer. Only last option is matching 

Answer: D

23)

Figure clearly explains the situation. Like in the above questions, use the principle of numbering system. Now, identify the projections and mark them as I did in the picture - Porjecion 1, proj 2, proj 3


Now, check the options that have depressions at the same location as projections are in the given question. Option C matches as shown in the picture.

24)

If you observe the middle shape (stick human figure), then he is not at the maximum height nor is falling down (In terms of physics - he is in the travel of ascent). In other words, he is moving away from earth (against the gravity) ans so the air will try to push hum down. It also tries to push his cape to the down. So, it's almost vertically downward - Option A matches. 

If he were to jump from top, or he is falling down, then the air will again try to oppose him in opposite direction to his travel, In other words towards up. So, the direction of the cape should also be vertical (In actual, the direction would most probably be in the curve (parabola) of the travel/path.

Answer : A

25)

Answer : A

26)

Answer : D


27)

This problem can be solved using your imagination/observation. Anyway as usual let me give one possible method

Method

Figure shows one possible shape of the nib which can draw as shown in the question. Remember Indians have the habit of drawing from left to right. And the given straight line is projected towards left. So, the nib should also project towards left as I showed in the picture.


Now, if you are to draw a circle, you will obviously start from the top and move in anti clockwise direction as shown in the image (b). Now, if you use the given nib, ans start drawing a circle, then you have to expect a sharp line (instead of broad width line) at the place where the nib moves parallely in the direction of the nib angle. To make it simple, if you assume tangent lines, drawn over the circle (b) as shown in (c)then the location on the circle at which the tangent angle is same as the nib angle is where the line will not be thick, got it ?

So, using this logic, option C is the answer. 

28) 

Answer : B

It's straight and I guess I don't have to explain this. If you still have doubts, then you may drop a comment, I will give proper explanations like I did for other questions.

29-30)

This question is usually solved by practising similar questions - by deriving logic from the given paragraph. I guess, I don't have to explain this.

Answers : 

29 - C
30 - A

Hope these explanations are simple and helped you ....... 
All the best :)

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21 comments:

  1. Is uceed an online xam or offline...plzz confirm me

    ReplyDelete
    Replies
    1. Purely Online - 3hr duration, 3 sections .........

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    2. Thanks for interacting and helping others too :)

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  2. it did a great help thanks god bless you ! i am really nervous about the exam as there are only 30 seats for iit bombay canyou please tell that at this moment what all we should go through ?

    ReplyDelete
    Replies
    1. Thank u
      Since only one day is left, mostly cover GA questions (if u have practised some thing on geo and observation ques), including envi. study. If possible, go thru samples of numerical and aptitude ques and memorize the procedure or steps used. Better skip comprehension type ques for now !

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    2. ohkay please give the link of some eneral awareness questions...

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    3. i have one more question it will be useful to go through dsource website of iit bombay at this moment...

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    4. You can find GA topics in this blogs resource page.

      dsource webpage has lot of topics that is definitely not useful for your exam. I suggest not to go through that at this point of time (only one day left !)

      Delete
    5. okk ya and it's really confusing somewhere.

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  3. In ques 5 of uceed 2015 ques paper; u hav solved it by taking 6*6*6 cube but in ques paper it is given to be 8*8*8.
    Please solve the ques accordingly.

    ReplyDelete
    Replies
    1. well, if u know the sol for 6x6x6, then you shouldn't have any problem solving for 8x8x8, try from your side and check the answer. Hopefully everyone can do this after checking my procedure for 6 sided cube!

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    2. but the answer mentioned in the answer key for 8*8*8 cube is 72.

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    3. Ya, I just went through my own solution, actually I gave pic for 6 side cube for understanding but solved the actual 8 sided cube problem, that's why you can see that the answer is 72. So, whatever explanation I gave 28+28+..... is for the actual 8 sided prob. Now I hope your confusion is cleared !

      Delete
    4. Could you please also go through the 2015 UCEED paper and post its solution. That would be tremendously helpful. Also, I couldn't find any book in your list that could tell me the answers to the questions like which painting is by Paul Klee or some other painter. I mean, how am I supposed to know all this?

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    5. Questions like who is the painter etc are GA type and has to be memorized with no other options or shortcut, Some famous painters/artists details are given in my blog ceed and uceed resource page. Rest you can just google it and get them. coming to uceed 2015 prev paper sol, if i get time, i will solve them and share asap.

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  4. The link to the official sample paper isn't working. If you have it saved in your computer, could you please upload that in dropbox and replace it with this link. Thanks. Also, do you know where I could get the art GA material(from the previous question?

    ReplyDelete
    Replies
    1. They have removed the page from their website, and updated with new link. I have changed the link, u may check now and download! sorry for the delay

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  5. the link to 2015 uceed official sample ppr is not wrking??

    ReplyDelete
    Replies
    1. New link has been uploaded, u may chk now

      Delete

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