tag:blogger.com,1999:blog-6452603028992718116.post2797701608085958820..comments2024-02-29T14:02:58.774+05:30Comments on Stuff You Look: Answer key to UCEED 2018 Previous paperBhanu Chander Vhttp://www.blogger.com/profile/08453570317960124174noreply@blogger.comBlogger43125tag:blogger.com,1999:blog-6452603028992718116.post-2112872770085858672022-12-12T15:16:29.857+05:302022-12-12T15:16:29.857+05:30Thanks Alka for the kind words. I will see if I ca...Thanks Alka for the kind words. I will see if I can work on last year's papers further. The problem is this blog's content is getting stolen and used as it is by the coaching institutes and so I lost motivation to make them. Anyway, I will try to make this time. Bhanu Chander Vhttps://www.blogger.com/profile/08453570317960124174noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-73716806429966705602022-12-11T23:58:50.797+05:302022-12-11T23:58:50.797+05:30Thank you so much sir
I have been following your ...Thank you so much sir <br />I have been following your you tube videos and blogs for my uceed 2023 prep , and these are really helpful. Sir I appreciate your hard work .<br /> Sir I am requesting you to please upload answers of uceed 2021 & 2022 part A as well.<br />Sir I know you have other things to do but sir your way of explanation just fits for me and i guess more students like me out there. Sir I am self preparing for uceed 23 and it will be great if you can do that.<br /> In case you can't still big appreciation for you :)Alka Bhttps://www.blogger.com/profile/08300911996462583027noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-17367946913569861172022-12-11T23:58:30.367+05:302022-12-11T23:58:30.367+05:30Thank you so much sir
I have been following your ...Thank you so much sir <br />I have been following your you tube videos and blogs for my uceed 2023 prep , and these are really helpful. Sir I appreciate your hard work .<br /> Sir I am requesting you to please upload answers of uceed 2021 & 2022 part A as well.<br />Sir I know you have other things to do but sir your way of explanation just fits for me and i guess more students like me out there. Sir I am self preparing for uceed 23 and it will be great if you can do that.<br /> In case you can't still big appreciation for you :)Alka Bhttps://www.blogger.com/profile/08300911996462583027noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-53342217635325220212022-11-24T15:01:19.843+05:302022-11-24T15:01:19.843+05:30Sir Q45 Answer is wrong it should be option A, B, ...Sir Q45 Answer is wrong it should be option A, B, C<br />Car headlight has concave lens and peephole has convex lens...Aarav Dixithttps://www.blogger.com/profile/15487053504075585551noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-62908100521846626812022-01-14T17:13:16.744+05:302022-01-14T17:13:16.744+05:30Can someone explain the 2nd qn again, if it's ...Can someone explain the 2nd qn again, if it's odd numbers shouldn't it be 115 after the '?'Anonymoushttps://www.blogger.com/profile/12894318616887024912noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-49426254076283516892021-10-10T12:18:53.487+05:302021-10-10T12:18:53.487+05:30Hello sir, could you recheck the ans for question ...Hello sir, could you recheck the ans for question 79 <br />The answer is (c)Anonymoushttps://www.blogger.com/profile/03931414740909586016noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-20002578512128050562021-07-11T07:53:59.100+05:302021-07-11T07:53:59.100+05:30sir can u explain q.68 bit easier ...the minute ha...sir can u explain q.68 bit easier ...the minute hand sceneAnonymoushttps://www.blogger.com/profile/00934801949572921391noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-32789820594441282242021-07-07T17:57:35.623+05:302021-07-07T17:57:35.623+05:30in q.40 not all are warli paintings.in q.40 not all are warli paintings.Anonymoushttps://www.blogger.com/profile/00934801949572921391noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-70380364791310305902021-01-15T22:19:32.769+05:302021-01-15T22:19:32.769+05:30Sir, the answer for question number 73 is c but th...Sir, the answer for question number 73 is c but the options are confusingAadit R Nhttps://www.blogger.com/profile/15063430960206676144noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-90731719454127270562021-01-15T11:37:44.457+05:302021-01-15T11:37:44.457+05:30Q.17
Rectangles (White,Red,Black) Ratios are same
...Q.17<br />Rectangles (White,Red,Black) Ratios are same<br />By observation Red Rectangle ( Length, Breath ) = 2 X White Rectangle (Length, Breath)<br />Same Way <br />Black Rectangle (L, B) = 2 X Red Rectanle ( L , B)<br />From That<br />White Rectangle in the Centre<br />Breath = 4<br />Length = 6<br />Red Rectangle<br />Breath = 4 X 2 = 8<br />Length = 6 X 2 = 12<br />Black Rectangle At Outer<br />Breath = 8 X 2 = 16<br />Length = 12 X 2 = 24<br />So<br />In Triangle ABC<br />BC = Breath of Black Rectangle = 16<br />AC = Half the Length of Black Rectanle (24/2) = 12<br />So<br />AB = Sqrt ( BC^2 + AC^2)<br />AB = Sqrt ( 16X16 + 12X12 )<br />AB = Sqrt ( 256 + 144 ) <br />AB = Sqrt ( 400 )<br />AB = 20<br /><br /><br /> Anonymoushttps://www.blogger.com/profile/16874163369465738949noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-31865803388862452232021-01-04T23:38:20.137+05:302021-01-04T23:38:20.137+05:30I think question 7 can be done using mid-point the...I think question 7 can be done using mid-point theorem. Length of white triangle will be half of the base of red rectangle.<br />i.e 6 = 1/2 of L .. then L is 12 .. length of red rectangle. Since proportion is same i.e 3:2 .. breadth will be 8. And breadth of red rectangle is half of black , so black's breadth is 16 and length is 24 . And in triangle ABC, length of AC is 1/2 of 24 which is 12. Now we can apply pythegoras. Ans will be 20.Sritama haithttps://www.blogger.com/profile/16586271982052886806noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-40050354528390280152021-01-04T21:15:44.023+05:302021-01-04T21:15:44.023+05:30Sir, in question 7, should we cut the torus(vada) ...Sir, in question 7, should we cut the torus(vada) horizontally into 2 pieces and place one above and one below the cylinder?Anonymoushttps://www.blogger.com/profile/16783227736449096176noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-34082418459214912132020-12-25T15:00:58.923+05:302020-12-25T15:00:58.923+05:30clap clapclap clapAnonymoushttps://www.blogger.com/profile/09845563920479553791noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-48868824012295825982020-01-11T10:01:21.320+05:302020-01-11T10:01:21.320+05:30In question 19 uceed 2018 (NAT), i thnk 2 is the a...In question 19 uceed 2018 (NAT), i thnk 2 is the answer..bcs we can keep one box digonolly fitting the room and the other box diogonally fitting the first box.Anonymoushttps://www.blogger.com/profile/06863481398565842929noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-51336092062846452592019-12-25T12:18:12.737+05:302019-12-25T12:18:12.737+05:30Hey!..About the 6th QUESTION: Cant we just divide ...Hey!..About the 6th QUESTION: Cant we just divide the VOLUME of the bigger cuboid by that of the smaller cuboid?? (its much easier than actually stacking each cuboid as it has more room for error )<br /><br />ie. dividing (3 x 3 x 11) by (2 x 1 x 1)<br /> we get: (99 divided by 2) =49.5<br /> but..we gotta take the WHOLE NUMBER(49) as the ANSWER because we want the no. of WHOLE CUBOIDS right.... :) Siddharth Mhttps://www.blogger.com/profile/13868997081773191923noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-3550636662583169852019-12-25T12:11:54.646+05:302019-12-25T12:11:54.646+05:30For Qn. 6 , can't we just divide the volume of...For Qn. 6 , can't we just divide the volume of the bigger cuboid by the smaller cuboid....and note down the "whole number value" of the division?<br />ie.: (3*3*11) divided by (2*1*1)<br /> which gives us: 99 divided by 2 = 49.5<br /> but we take 49 as the ans. because we want "Whole cuboids" to fit. Siddharth Mhttps://www.blogger.com/profile/13868997081773191923noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-1923497504992893782019-12-17T11:44:02.900+05:302019-12-17T11:44:02.900+05:30According to the third fig we
Can split the fig i...According to the third fig we<br />Can split the fig in to 4 triangles substitute it in fig 5 and then in fig 4Vhttps://www.blogger.com/profile/07612906360824314284noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-83202060693107416902019-11-09T00:37:49.834+05:302019-11-09T00:37:49.834+05:30sir pls explain 53sir pls explain 53Anonymoushttps://www.blogger.com/profile/11760201839640213727noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-10259884342894162472019-10-14T17:43:54.458+05:302019-10-14T17:43:54.458+05:30for qs 17 i get the ans as 20 which is also very c...for qs 17 i get the ans as 20 which is also very close to 19.23<br />by using pythagoraous theorem AB^2 + BC^2= AC^2<br />I ASSUMED THE VALUES BY MEASURING WITH MY PENCILKRISHI JAINhttps://www.blogger.com/profile/10045002325116681102noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-43490976487151807342019-05-19T11:03:41.408+05:302019-05-19T11:03:41.408+05:30Sir please post the solution of uceed 2019 questio...Sir please post the solution of uceed 2019 question paperyadavhttps://www.blogger.com/profile/16811438707951045647noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-89114598053388315152019-01-27T09:39:23.009+05:302019-01-27T09:39:23.009+05:30please reply
please reply<br />Anonymoushttps://www.blogger.com/profile/11182380610966870242noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-22032083480812399622019-01-25T19:14:12.956+05:302019-01-25T19:14:12.956+05:30Hi sir...Please could you upload the answers to uc...Hi sir...Please could you upload the answers to uceed 2019 ACCORDING TO YOU as we have to send the discrepancies in the answer key by 31st January...Till now i have been dependent on your material for my prep...now also i'm dependent on u for ur solutions so please _/\_ upload as soon as possibleAnonymoushttps://www.blogger.com/profile/11182380610966870242noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-85237758002014051592019-01-15T22:16:10.549+05:302019-01-15T22:16:10.549+05:30sir , could you please explain how to solve questi...sir , could you please explain how to solve question 53?mathangihttps://www.blogger.com/profile/15113720816256755028noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-55764855522039357592019-01-12T00:00:12.435+05:302019-01-12T00:00:12.435+05:30sir i didnt get q 56 . can u explain it again
sir i didnt get q 56 . can u explain it again <br />Anonymoushttps://www.blogger.com/profile/10679871063159979381noreply@blogger.comtag:blogger.com,1999:blog-6452603028992718116.post-78893009258032830312019-01-11T09:55:02.523+05:302019-01-11T09:55:02.523+05:30Sir 7th pls. Discuss again. Sir 7th pls. Discuss again. Anonymoushttps://www.blogger.com/profile/01982792547334374853noreply@blogger.com